Question

Decreasing Combinations of Stieltjes Coefficients

score 70 · Answer 1 · 2018-05-29 16:36:04

70

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Decreasing Combinations of Stieltjes Coefficients

Published on 29 May 2018 - 16:36

score 111 · Answer 2 · 2026-03-22 05:38:00

111

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Variant of Stieltjes constants

Published on 22 Mar 2026 - 5:38

score 148 · Answer 3 · 2019-04-04 22:29:05

148

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Calculation of Integrals with reciproce Logarithm, Euler's constant $\gamma=0.577...$

Published on 04 Apr 2019 - 22:29

score 1.8k · Answer 4 · 2026-03-21 05:42:05

1.8k

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A closed form of the series $\sum_{n=1}^{\infty} \frac{H_n^2-(\gamma + \ln n)^2}{n}$

Published on 21 Mar 2026 - 5:42

score 181 · Answer 5 · 2026-03-21 05:42:05

181

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What is the sign of the generalized Stieltjes constants $\gamma_{k}(a)$?

Published on 21 Mar 2026 - 5:42

score 351 · Answer 6 · 2026-03-21 05:42:05

351

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Question on the paper Donal F. Connon, "Some integrals involving the Stieltjes constants"

Published on 21 Mar 2026 - 5:42

score 937 · Answer 7 · 2026-03-21 05:42:05

937

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A couple of definite integrals related to Stieltjes constants

Published on 21 Mar 2026 - 5:42

score 629 · Answer 8 · 2020-04-25 20:09:11

629

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Showing $\zeta(s)-{1\over s-1}$ is analytic

Published on 25 Apr 2020 - 20:09

score 125 · Answer 9 · 2020-07-31 06:27:20

125

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Is $\zeta(x)>\frac{1}{x-1}$ when $1<x<2$?

Published on 31 Jul 2020 - 6:27

score 384 · Answer 10 · 2026-03-21 05:42:05

384

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Asymptotic behavior of Harmonic-like series $\sum_{n=1}^{k} \psi(n) \psi'(n) - (\ln k)^2/2$ as $k \to \infty$

Published on 21 Mar 2026 - 5:42

score 102 · Answer 11 · 2023-11-25 17:05:50

102

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Proving that $\int_{0}^{1}\left(\zeta(t)+\frac{1}{1-t}\right)dt=\sum_{n=0}^{\infty}\frac{\gamma_{n}}{(n+1)!}$

Published on 25 Nov 2023 - 17:05

score 33 · Answer 12 · 2023-12-17 02:36:18

33

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Regularization involving Stieltjes constants: $\displaystyle\sum_{k=1}^{\infty}\frac{\ln(k)^n}{k}\overset{\mathcal{R}}{=}\gamma_n$

Published on 17 Dec 2023 - 2:36

score 581 · Answer 13 · 2015-04-11 14:00:17

581

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Calculate the infinite sum $\sum_{1}^\infty \frac{\log{n}}{2n-1}$

Published on 11 Apr 2015 - 14:00

score 221 · Answer 14 · 2016-01-11 18:14:16

221

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Series for Stieltjes constants from $\gamma= \sum_{n=1}^\infty \left(\frac{2}{n}-\sum_{j=n(n-1)+1}^{n(n+1)} \frac{1}{j}\right)$

Published on 11 Jan 2016 - 18:14

score 1.7k · Answer 15 · 2026-03-21 04:07:12

1.7k

Views

The asymptotic expansion for the weighted sum of divisors $\sum_{n\leq x} \frac{d(n)}{n}$

Published on 21 Mar 2026 - 4:07

List Question

Decreasing Combinations of Stieltjes Coefficients

Variant of Stieltjes constants

Calculation of Integrals with reciproce Logarithm, Euler's constant $\gamma=0.577...$

A closed form of the series $\sum_{n=1}^{\infty} \frac{H_n^2-(\gamma + \ln n)^2}{n}$

What is the sign of the generalized Stieltjes constants $\gamma_{k}(a)$?

Question on the paper Donal F. Connon, "Some integrals involving the Stieltjes constants"

A couple of definite integrals related to Stieltjes constants

Showing $\zeta(s)-{1\over s-1}$ is analytic

Is $\zeta(x)>\frac{1}{x-1}$ when $1<x<2$?

Asymptotic behavior of Harmonic-like series $\sum_{n=1}^{k} \psi(n) \psi'(n) - (\ln k)^2/2$ as $k \to \infty$

Proving that $\int_{0}^{1}\left(\zeta(t)+\frac{1}{1-t}\right)dt=\sum_{n=0}^{\infty}\frac{\gamma_{n}}{(n+1)!}$

Regularization involving Stieltjes constants: $\displaystyle\sum_{k=1}^{\infty}\frac{\ln(k)^n}{k}\overset{\mathcal{R}}{=}\gamma_n$

Calculate the infinite sum $\sum_{1}^\infty \frac{\log{n}}{2n-1}$

Series for Stieltjes constants from $\gamma= \sum_{n=1}^\infty \left(\frac{2}{n}-\sum_{j=n(n-1)+1}^{n(n+1)} \frac{1}{j}\right)$

The asymptotic expansion for the weighted sum of divisors $\sum_{n\leq x} \frac{d(n)}{n}$

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