Question

Error/convergence analysis using Taylor expansion for a root-finding method

score 123 · Answer 1 · 2026-03-26 07:31:54

123

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Error/convergence analysis using Taylor expansion for a root-finding method

Published on 26 Mar 2026 - 7:31

score 81 · Answer 2 · 2026-04-13 16:45:44

81

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Taylor series expansions with a small variable parameter and derivatives

Published on 13 Apr 2026 - 16:45

score 59 · Answer 3 · 2026-04-16 08:29:39

59

Views

Taylor polynomials with "gappy data"

Published on 16 Apr 2026 - 8:29

score 66 · Answer 4 · 2026-04-12 16:04:14

66

Views

Explanation to "recurrence relation" of Taylor's series (how did we come up with coefficients and where are factorials?)

Published on 12 Apr 2026 - 16:04

score 239 · Answer 5 · 2026-04-15 05:27:36

239

Views

Taylor series of $e^{-1/x^2}$ about $x = 0$

Published on 15 Apr 2026 - 5:27

score 70 · Answer 6 · 2026-04-13 13:26:26

70

Views

Calculer la limite de la suite suivante: $\frac{ a_n(y_n) }{e^{y_n}}$

Published on 13 Apr 2026 - 13:26

score 58 · Answer 7 · 2026-04-17 11:59:12

58

Views

Evaluate $\lim_{x \to \infty} (e^{\frac{1}{x}}(x^3 - x^2 + \frac{x}{2}) - \sqrt{x^6 +1})$ using Taylor

Published on 17 Apr 2026 - 11:59

score 26 · Answer 8 · 2026-04-16 20:08:59

26

Views

Taylor Expansion of $\log \left( 1+\frac{4.645}{\sqrt{R\cdot S}} \right)$

Published on 16 Apr 2026 - 20:08

score 63 · Answer 9 · 2026-04-09 04:49:53

63

Views

Solving limit using taylor series and little-o

Published on 09 Apr 2026 - 4:49

score 150 · Answer 10 · 2026-04-16 17:21:09

150

Views

$f$ is twice continuously differentiable on $\mathbb{R}^n$, $x$ is a local minimiser, show that $\nabla^2f(x)$ is positive semidefinite

Published on 16 Apr 2026 - 17:21

score 54 · Answer 11 · 2026-04-18 12:00:08

54

Views

$|\frac{x^h -1}{h}-\log(x)|\leq \frac{|h||\log(x)|^2 }{2}\exp(|h\log(x)|), \quad 0<|h|<1.$

Published on 18 Apr 2026 - 12:00

score 127 · Answer 12 · 2026-04-10 15:58:06

127

Views

Need help using Taylor series expansion to evaluate a limit

Published on 10 Apr 2026 - 15:58

score 175 · Answer 13 · 2026-04-16 12:45:24

175

Views

Need help determining Taylor series and convergence interval for $f(x)=1/x$ around $x=1$

Published on 16 Apr 2026 - 12:45

score 164 · Answer 14 · 2026-04-14 03:09:45

164

Views

Getting the original function from a Taylor series

Published on 14 Apr 2026 - 3:09

score 62 · Answer 15 · 2026-03-25 06:34:24

62

Views

Branch points of $\sqrt{\cos(z)}$.

Published on 25 Mar 2026 - 6:34

List Question

Error/convergence analysis using Taylor expansion for a root-finding method

Taylor series expansions with a small variable parameter and derivatives

Taylor polynomials with "gappy data"

Explanation to "recurrence relation" of Taylor's series (how did we come up with coefficients and where are factorials?)

Taylor series of $e^{-1/x^2}$ about $x = 0$

Calculer la limite de la suite suivante: $\frac{ a_n(y_n) }{e^{y_n}}$

Evaluate $\lim_{x \to \infty} (e^{\frac{1}{x}}(x^3 - x^2 + \frac{x}{2}) - \sqrt{x^6 +1})$ using Taylor

Taylor Expansion of $\log \left( 1+\frac{4.645}{\sqrt{R\cdot S}} \right)$

Solving limit using taylor series and little-o

$f$ is twice continuously differentiable on $\mathbb{R}^n$, $x$ is a local minimiser, show that $\nabla^2f(x)$ is positive semidefinite

$|\frac{x^h -1}{h}-\log(x)|\leq \frac{|h||\log(x)|^2 }{2}\exp(|h\log(x)|), \quad 0<|h|<1.$

Need help using Taylor series expansion to evaluate a limit

Need help determining Taylor series and convergence interval for $f(x)=1/x$ around $x=1$

Getting the original function from a Taylor series

Branch points of $\sqrt{\cos(z)}$.

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