Question

Parallelogram Inequality

score 194 · Answer 1 · 2020-06-25 06:41:16

194

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Parallelogram Inequality

Published on 25 Jun 2020 - 6:41

score 530 · Answer 2 · 2020-07-02 12:22:10

530

Views

If $ABC$ is a right angled triangle at $C$ then prove that $a^n+b^n<c^n$ for all $n>2$

Published on 02 Jul 2020 - 12:22

score 119 · Answer 3 · 2020-07-09 09:43:13

119

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Why does $\left|\frac{\sin(n+1)}{2^{n+1}}+...+\frac{\sin(n+p)}{2^{n+p}}\right|\leq\frac{|\sin(n+1)|}{2^{n+1}}+...+\frac{|\sin(n+p)|}{2^{n+p}}$ hold?

Published on 09 Jul 2020 - 9:43

score 90 · Answer 4 · 2020-07-11 10:24:40

90

Views

If $\int_a^b f(x)dx=\left[F(x)\right]_a^b$, Is $\int_a^b \lvert f(x)\rvert dx= \left[\lvert F(x)\rvert \right]_a^b$ true?

Published on 11 Jul 2020 - 10:24

score 193 · Answer 5 · 2020-07-14 16:48:56

193

Views

Proving $\sqrt{x^2-xz+z^2} + \sqrt{y^2-yz+z^2} \geq \sqrt{x^2+xy+y^2}$ algebraically

Published on 14 Jul 2020 - 16:48

score 280 · Answer 6 · 2020-07-16 04:35:34

280

Views

in the triangle ABC on the AC side, points M and N are chosen such that ABM = MBN = NBC

Published on 16 Jul 2020 - 4:35

score 208 · Answer 7 · 2020-07-17 06:53:51

208

Views

How to prove that if $x>0$ and $y>0$, then $\sqrt{x}+\sqrt{y}>\sqrt{x+y}$, using the relation of arithmetic and geometric means?

Published on 17 Jul 2020 - 6:53

score 99 · Answer 8 · 2020-07-19 17:32:16

99

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$|x-a| < \epsilon$ , $|y-a| < \epsilon$ (where $x,y,a\in\mathbb R $ and $\epsilon>0$). Use the Triangle Inequality to find an estimate for $|x-y|$

Published on 19 Jul 2020 - 17:32

score 116 · Answer 9 · 2020-07-22 12:57:58

116

Views

On Resolving a Fuss on Squares and Fractions over a few Inequalities

Published on 22 Jul 2020 - 12:57

score 337 · Answer 10 · 2020-07-24 06:34:02

337

Views

how to check triangle inequality in definition of norm

Published on 24 Jul 2020 - 6:34

score 72 · Answer 11 · 2020-07-26 02:46:08

72

Views

What Inequality holds true if and only if when $|x|+|y|+|z|+|x+y+z|=|x+y|+|y+z|+|z+x|$ is true?

Published on 26 Jul 2020 - 2:46

score 230 · Answer 12 · 2020-07-27 18:49:29

230

Views

Prove $\sqrt{\sum^n_{k=1}(a_k+b_k)^2} \leq \sqrt{\sum^n_{k=1}(a_k)^2} + \sqrt{\sum^n_{k=1}(b_k)^2}$.

Published on 27 Jul 2020 - 18:49

score 64 · Answer 13 · 2020-07-29 04:47:06

64

Views

Finding modulus of a complex number

Published on 29 Jul 2020 - 4:47

score 54 · Answer 14 · 2023-01-31 22:47:35

54

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L1 norm of (L1 normalized vector minus original vector) less than or equal to 1 minus the L1 norm of the original vector

Published on 31 Jan 2023 - 22:47

score 188 · Answer 15 · 2023-02-19 18:21:11

188

Views

Equality case in metric spaces

Published on 19 Feb 2023 - 18:21

List Question

Parallelogram Inequality

If $ABC$ is a right angled triangle at $C$ then prove that $a^n+b^n<c^n$ for all $n>2$

Why does $\left|\frac{\sin(n+1)}{2^{n+1}}+...+\frac{\sin(n+p)}{2^{n+p}}\right|\leq\frac{|\sin(n+1)|}{2^{n+1}}+...+\frac{|\sin(n+p)|}{2^{n+p}}$ hold?

If $\int_a^b f(x)dx=\left[F(x)\right]_a^b$, Is $\int_a^b \lvert f(x)\rvert dx= \left[\lvert F(x)\rvert \right]_a^b$ true?

Proving $\sqrt{x^2-xz+z^2} + \sqrt{y^2-yz+z^2} \geq \sqrt{x^2+xy+y^2}$ algebraically

in the triangle ABC on the AC side, points M and N are chosen such that ABM = MBN = NBC

How to prove that if $x>0$ and $y>0$, then $\sqrt{x}+\sqrt{y}>\sqrt{x+y}$, using the relation of arithmetic and geometric means?

$|x-a| < \epsilon$ , $|y-a| < \epsilon$ (where $x,y,a\in\mathbb R $ and $\epsilon>0$). Use the Triangle Inequality to find an estimate for $|x-y|$

On Resolving a Fuss on Squares and Fractions over a few Inequalities

how to check triangle inequality in definition of norm

What Inequality holds true if and only if when $|x|+|y|+|z|+|x+y+z|=|x+y|+|y+z|+|z+x|$ is true?

Prove $\sqrt{\sum^n_{k=1}(a_k+b_k)^2} \leq \sqrt{\sum^n_{k=1}(a_k)^2} + \sqrt{\sum^n_{k=1}(b_k)^2}$.

Finding modulus of a complex number

L1 norm of (L1 normalized vector minus original vector) less than or equal to 1 minus the L1 norm of the original vector

Equality case in metric spaces

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