Question

$v(n!)=\sum_{i=1}^\infty [\frac{n}{p^i}]v(p)$ AEC lemma IV. 6.2

score 53 · Answer 1 · 2021-03-22 00:29:05

53

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$v(n!)=\sum_{i=1}^\infty [\frac{n}{p^i}]v(p)$ AEC lemma IV. 6.2

Published on 22 Mar 2021 - 0:29

score 101 · Answer 2 · 2021-03-22 14:50:45

101

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Characterizing Totally Ramified Extensions

Published on 22 Mar 2021 - 14:50

score 316 · Answer 3 · 2021-03-24 05:35:26

316

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Number of valuation ring of a given field

Published on 24 Mar 2021 - 5:35

score 536 · Answer 4 · 2021-03-25 14:49:18

536

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number of valuation ring of $\Bbb Q_p((T))$

Published on 25 Mar 2021 - 14:49

score 51 · Answer 5 · 2021-03-26 16:45:09

51

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Valuation defined on arbitrary commutative ring

Published on 26 Mar 2021 - 16:45

score 120 · Answer 6 · 2026-02-23 01:21:12

120

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Let $（K,v）$ be character 0 field complete with discrete normalized valuation is always non Archimedean?

Published on 23 Feb 2026 - 1:21

score 236 · Answer 7 · 2026-02-23 19:23:36

236

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Can inseparable elements “appear” in the residue field of the Galois closure of a field extension with separable residue field extension?

Published on 23 Feb 2026 - 19:23

score 42 · Answer 8 · 2021-04-17 13:17:36

42

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Why are valuations over a prime ideal well-defined in number fields?

Published on 17 Apr 2021 - 13:17

score 45 · Answer 9 · 2021-04-19 19:45:04

45

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$v(n!)＝\sum_{i=1}^{\infty} [\dfrac{n}{p^i}]v(p)$

Published on 19 Apr 2021 - 19:45

score 80 · Answer 10 · 2021-04-20 06:29:17

80

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How to show finiteness in Exercise 12.4 of Matsumura?

Published on 20 Apr 2021 - 6:29

score 179 · Answer 11 · 2021-04-28 23:31:12

179

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An equivalent definition of valuation rings

Published on 28 Apr 2021 - 23:31

score 76 · Answer 12 · 2021-04-29 11:59:36

76

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DVR which does not contain $\mathbb{Z}$

Published on 29 Apr 2021 - 11:59

score 52 · Answer 13 · 2021-04-29 15:01:35

52

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Let $v$ be a valuation of DVR of character 0, If $v(p)＞0$, then for all $q≠p$, $v(q)＝0$

Published on 29 Apr 2021 - 15:01

score 34 · Answer 14 · 2021-04-30 22:20:47

34

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Let $(R,M)$ be DVR and $v$ be its valuation. And $p$ be a character of its residue field. In the case $p≠0$,can we say $v(p)＝∞$?

Published on 30 Apr 2021 - 22:20

score 171 · Answer 15 · 2021-05-04 03:50:30

171

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Discrete valuation on $\mathbb{F}_p[[t]]$

Published on 04 May 2021 - 3:50

List Question

$v(n!)=\sum_{i=1}^\infty [\frac{n}{p^i}]v(p)$ AEC lemma IV. 6.2

Characterizing Totally Ramified Extensions

Number of valuation ring of a given field

number of valuation ring of $\Bbb Q_p((T))$

Valuation defined on arbitrary commutative ring

Let $（K,v）$ be character 0 field complete with discrete normalized valuation is always non Archimedean?

Can inseparable elements “appear” in the residue field of the Galois closure of a field extension with separable residue field extension?

Why are valuations over a prime ideal well-defined in number fields?

$v(n!)＝\sum_{i=1}^{\infty} [\dfrac{n}{p^i}]v(p)$

How to show finiteness in Exercise 12.4 of Matsumura?

An equivalent definition of valuation rings

DVR which does not contain $\mathbb{Z}$

Let $v$ be a valuation of DVR of character 0, If $v(p)＞0$, then for all $q≠p$, $v(q)＝0$

Let $(R,M)$ be DVR and $v$ be its valuation. And $p$ be a character of its residue field. In the case $p≠0$,can we say $v(p)＝∞$?

Discrete valuation on $\mathbb{F}_p[[t]]$

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