Consider the set $X=\{2, 3, 4, 5, 6, 7, 8, 9, 10\}$ endowed with the order $$x\leq y\Leftrightarrow y|x,$$ that is, $x$ precedes $y$ if and only if $y$ is a divisor of $x$. Can anyone check whether my Hasse diagram below is correct? And what are the minimal and maximal elements?
I guess the minimal elements are $6$, $7$, $8$, $9$ and $10$ whereas the maximal elements are $2$, $3$, $5$, $7$. Am I right?
Thanks