I want to express the following in logical notation.
For every natural number, there is a unique natural number that succeeds it.
Does the following statement express that proposition?
$\forall n(n\in \mathbb{N} \rightarrow (\exists !m(m\in\mathbb{N} \wedge m=n+1))$
Thank you,
-Hal
Yes, you've done a good job expressing the proposition, using logical notation.