This should be easy, but I feel like I'm missing something. I work for this exam, and I don't understand why:
$\forall x,y\in(2,+\infty):$
$$(x-2)^{\ln(y-2)/3}=e^{\ln(x-2)\ln(y-2)/3}.$$
This should be easy, but I feel like I'm missing something. I work for this exam, and I don't understand why:
$\forall x,y\in(2,+\infty):$
$$(x-2)^{\ln(y-2)/3}=e^{\ln(x-2)\ln(y-2)/3}.$$
if this is your question :$$(−2)^{(1/3((−2)))}=^{(1/3(−2)(−2))}$$ $a=e^{ln(a)}$ or $x-2=e^{ln(x-2)}$