Help proving Sylow's Theorem order 58

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Prove that every group of order 58 is not simple. So I know that 58 = 2 ⋅ 29. I assume G is simple. I'm having trouble using the Sylow Theorems to show that this is not Simple. In particular, computing the number of sylow groups and using that to show the group isn't Simple

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Let $P \in Syl_{29}(G)$. Such a $P$ exists by Sylow's (First) Theorem (or just by Cauchy's Theorem). Then $|G:P|=2$ and it is basic group theory knowledge that subgroups of index $2$ are normal. So $G$ cannot be simple.