I've been trying to solve this problem for a good 2 hours and I still couldn't find the solution please help.
$$ \left\{ \begin{array}{c} 4x^2-3xy-y^2=0 \\ 32x^2-36xy+9y^2=6 \\ \end{array} \right. $$
2026-03-26 22:51:42.1774565502
Help solving system of equations
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From the first equation, you get
$$\begin{equation}\begin{aligned} 4x^2 - 3xy - y^2 & = 0 \\ (4x + y)(x - y) & = 0 \end{aligned}\end{equation}\tag{1}\label{eq1A}$$
which gives that
$$y = -4x \; \text{ or } \; y = x \tag{2}\label{eq2A}$$
Substitute these $2$ possibilities into the second equation & simplify the results. Do you think you can finish the rest?