Help to find limit of this function:
$\lim \limits_{x \to 3} \frac{sin(\sqrt{2x^2-3x-5} -\sqrt{1+x} )}{\ln(x-1)-\ln(x+1)+\ln2}$
I tried myself to solve this limit, but i unsure with answer.
$\frac{0}{0}$=$\lim \limits_{x \to 3} $$\frac{cos(sqrt{2x^2-3x-5}-sqrt{1+x})}{\frac{1}{x-1}-\frac{1}{x+1}}(\frac{4x-3}{2sqrt{2x^2-3x-5}}-\frac{1}{2\sqrt{1+x}}) =$
$\lim \limits_{x \to 3}\frac{2}{1-\frac{1}{4}}=8$
2026-04-02 19:46:40.1775159200
Help to find the limit of function
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