Does anyone have any idea how to prove this?
/[P ⊃ (Q ⊃ R)] ⊃ [(P ⊃ Q) ⊃ (P ⊃ R)]
So far I have
1' P ⊃ (Q ⊃ R) AcP
2' P ⊃ Q AcP
3' ~P AIP
Thanks
Does anyone have any idea how to prove this?
/[P ⊃ (Q ⊃ R)] ⊃ [(P ⊃ Q) ⊃ (P ⊃ R)]
So far I have
1' P ⊃ (Q ⊃ R) AcP
2' P ⊃ Q AcP
3' ~P AIP
Thanks
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Standard notation is "$\to$" for "implies" because "$\supset$" denotes "[strict] superset". Also, "$\neg$" is standard for "not".
I'll leave you to fill in the final steps and the justification for each step.