Help with solving this fraction

Question

Solve for $h$:
$$125=\pi \left (\dfrac{5}{\sqrt[3]{\pi}} \right )^2h$$

This is from an optimization problem, in which the volume is the constraint of $125$. I've done everything in the problem except finding this last dimension $h$. The answer is $h=\dfrac{5}{\sqrt[3]{\pi}}$, but I can't seem to get that. Can you show steps please? Thanks.

Answer 1

$$125 = \frac{25 \pi}{\pi^{2/3}}h = 25\pi^{1/3}h \to h = \frac{5}{\pi^{1/3}}.$$

Answer 2

Note that

$$\pi \left(\frac{5}{\sqrt[3]{\pi}}\right)^2 = \frac{25 \pi}{\sqrt[3]{\pi}^2} = 25 \sqrt[3]{\pi}$$