I don't understand why
$$ptf(x)h(x)^{p-1}\leq (h(x)+tf(x))^p-h(x)^p$$.
As Thomas Shelby's question comment states, it follows from the lemma of
$$(a + tb)^p \ge a^p + ptba^{p-1} \implies ptba^{p-1} \le (a + tb)^p - a^p \tag{1}\label{eq1A}$$
Using $a = h(x)$ and $b = f(x)$ in \eqref{eq1A} gives what you're asking about, i.e.,
$$ptf(x)h(x)^{p-1}\leq (h(x)+tf(x))^p-h(x)^p \tag{2}\label{eq2A}$$
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As Thomas Shelby's question comment states, it follows from the lemma of
$$(a + tb)^p \ge a^p + ptba^{p-1} \implies ptba^{p-1} \le (a + tb)^p - a^p \tag{1}\label{eq1A}$$
Using $a = h(x)$ and $b = f(x)$ in \eqref{eq1A} gives what you're asking about, i.e.,
$$ptf(x)h(x)^{p-1}\leq (h(x)+tf(x))^p-h(x)^p \tag{2}\label{eq2A}$$