I know in the basic definition of a category you have the class hom(C) of morphisms between objects in the category C. What never seems to be clear from textbook definitions is this: Are the members of hom(C) the hom classes, hom(a,b), where a and b are object in C, or do they just slop all the morphisms between any of the objects in C together into a single class?
2026-04-13 06:25:49.1776061549
hom(C) in category theory
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To my knowledge there is not the way to make precise in the language of set theory the concept of a category, but at least the following two options exist. In the first, you naturally encounter $\text{hom}({\mathcal C})$ as the class of morphism sets, while in the second, you rather get $\hom({\mathcal C})$ as the class of all morphisms.
In this formulation, the morphism sets need not be disjoint. The image class of the class function $\text{hom}$ has as elements the hom-sets of your category, and its union is the class of all morphisms.
Alternatively, you can use:
In this formulation the morphism sets are indeed disjoint. The class of all homomorphism is ${\mathcal C}_1$, while the class of all hom-sets is the class of fibers of the class function $(s,t)$.
The latter formulation also fits well with how you define internal category objects in cartesian closed categories.