Let $f:\mathbb R^n \to \mathbb R$ be a homogeneous function of degree $p$. $f(tx)=t^pf(x)$ for $p>0$.
Let us assume that $f$ is continuously differentiable. How to show that $\frac{\partial f}{\partial x_i}$ is a homogeneous function of degree $p-1$?
I tried to use euler's theorem $(\nabla f(x),x)=kf(x)$ but didn't manage to prove it.
Thanks!
By the chain rule:
$$\frac{\partial}{\partial x_i}\Big[f(tx)\Big]=f_i(tx)\cdot t$$
and
$$\frac{\partial}{\partial x_i}\Big[t^pf(x)\Big]=t^pf_i(x)$$
Can you conclude?