How can I evaluate this summation?\begin{align}\sum_{n=1}^\infty\frac{1}{n(e^{2\pi n}-1)}=\,?\end{align}I have\begin{align}\sum_{n=1}^\infty\frac{n^{2m-1}}{e^{2\pi n}-1}=\frac{B_{2m}}{4m}\end{align}for odd m>1... or do I have to use mellin transform?
2026-03-28 13:33:45.1774704825
How can I evaluate this summation?
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