How can I find the intersecting curve? $x=6\cos (t+\frac\pi 3).y=3\sin t,z=u \text{ and } 0\leq t\leq 2\pi .u\in R$

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Question: Parametric equation of surface S is given below: $$x=6\cos (t+\frac\pi 3).y=3\sin t,z=u \text{ and } 0\leq t\leq 2\pi .u\in R$$

Find the curve which is intersecting with surface S's plane: $y={x\over\sqrt 3}$ and explain what type of intersection it is.

I can't seem to find a solution, can you help me, I mean can you show me a way to solve this question?