I tried, although didn't succeed. I got to the point where I have got $15 = 7 \cdot 2 + 1$. And then I have rearranged this for $1$.
In addition, is there a general way to solve these?
Thanks.
2026-03-28 16:44:20.1774716260
How can I find the multiplicative inverse of $7 \pmod{15}$?
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If you know $$15=7(2)+1$$
Let's consider $\mod 15$
$$0\equiv7(2)+1 \mod 15$$
$$7(-2) \equiv 1 \mod 15$$
Hence $$(13)7\equiv 1 \mod 15$$