How can I prove that if $|x| > |y|$ then $x^2 > y^2$

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How can I prove that if $|x| > |y|$ then $x^2 > y^2$ using proofs such as contradiction, direct proof.

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Faster, if you assume that $t \mapsto t^2$ is strictly growing on $[0 , \infty)$, then $x^2 < y^2$ if $|x| < |y|$.

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$|x| < |y| \implies |x||x| = |x|^2 = x^2 < |x||y| < |y||y| = |y|^2 = y^2$

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Direct Proof. Assume that $|x|>|y|$. Then $$x^2=|x^2|=|xx|=|x|\cdot|x|>|y|\cdot|y|=|y|^2=|y^2|=y^2.$$