How can I prove that for every function g that is bounded in interval I:
$\sup_{I}(g) - \inf_{I}(g) = \sup_{x,y \in I} |g(x) - g(y)|$
How can I prove that for every function g that is bounded in interval I:
$\sup_{I}(g) - \inf_{I}(g) = \sup_{x,y \in I} |g(x) - g(y)|$
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