How can I prove this ? $\sum\limits_{i=1}^N \frac{1}{\sin^2(\frac{i \pi}{2 N})} = \frac{1}{3}(2N^2+1)$

130 Views Asked by At

$$\sum_{i=1}^N \frac{1}{\sin^2(\frac{i \pi}{2 N})} = \frac{1}{3}(2N^2+1)$$

How can I prove this ?

Thank you.