I am just reading the first chapter of the Introduction to Analysis of the Infinite and get stuck here:

How did he derive $z^2-2(p+qi)z+r+si$ and $z^2-2(p-qi)z+r-si$ for the function $z^4+Az^3+Bz^2+Cz+D$
What about the four complex linear factors? How did he derive it?
Thank you!
To derive the two complex quadratic factors, consider the product of two linear complex factors like $$ (z - (k+li))(z - (m+ni)) \\ = z^2 - ((k+li)+(m+ni))z + (k+li)(m+ni) \\ = z^2 - ((k+m)+(l+n)i)z + ((km-ln) + (kn+lm)i) $$ If you let $p=k+m$, $q=l+n$, $r=km-ln$ and $s=kn+lm$ we then have $$ z^2 - (p+qi)z + r + si $$ This explains the negative coefficient of the first-degree term which is further explained if you consider that the sum of the roots should equal $p+qi$ and the product should equal $r+si$. Using the quadratic formula, let's convince ourselves of the sum with $$ \left(\frac{p+qi+\sqrt{(p+qi)^2-4(r+si)}}{2}\right) + \left(\frac{p+qi-\sqrt{(p+qi)^2-4(r+si)}}{2}\right) \\ = \frac{(p+qi)+(p+qi)}{2} \\ = p+qi $$ The presence of a denominator in the quadratic formula makes the calculation awkward, so it can be removed by multipling numerator and therefore the first-degree coefficient by $2$ $$ \frac{2(p+qi)\pm\sqrt{[2(p+qi)]^2-4(r+si)}}{2} \\ = (p+qi)\pm\sqrt{(p+qi)^2-(r+si)} \\ = (p+qi)\pm\sqrt{p^2+2pqi-q^2-r-si} $$ This, combined with the previous explanation, explains the $-2$ coefficient of the first-degree term which also happens to explain the first two of the four complex linear factors. The last two can be explained if I had started this answer with the product of two linear complex factors like $$ (z-(k-li))(z-(m-ni)) $$