Is there a constant time mathematical approach to calculate the sum of sum of two integer arrays such that the common numbers are counted only once?
For example, Sum of A1= {2,3} = 5 and
Sum of A2= {2,4} = 6
Can I have a mathematical equation to calculate the sum to be of 2+3+4 instead of counting 2 twice as 2+2+3+4?
Note: An efficient solution to the above problem would help solve the overall problem of finding pairwise intersections of a given list of subsets of an Universal set {1,2,3,4,....,n}
I think you want to sum the union.
$$\sum_{x \in A \cup B} x$$
It can't be constant time as you need to check what are the elements.
Alternative approach:
$$\sum_{x\in A \cup B} x = \sum_{x\in A}x + \sum_{x \in B}x-\sum_{x \in A \cap B}x$$