The original integral is:
$\int_{0}^{3}\int_{0}^{\sqrt{9-z^2}}\int_{0}^{\sqrt{9-y^{2}-z^{2}}}dxdydz$
I am asked to change this into an integral with the order of $dzdydx$. How do I do this? I have no idea where to start.
The original integral is:
$\int_{0}^{3}\int_{0}^{\sqrt{9-z^2}}\int_{0}^{\sqrt{9-y^{2}-z^{2}}}dxdydz$
I am asked to change this into an integral with the order of $dzdydx$. How do I do this? I have no idea where to start.
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A hint:
This triple integral serves to compute the volume of a certain three-dimensional body $B$. Before you start interchanging the order of integration get a clear pictorial idea of what this body is. When this is accomplished set up the order of integration as prescribed.