The first equation is
$$a=\sqrt{\left(\cos\left(g\right)\sqrt{y\left(b-d\right)^2+y\left(a-c\right)^2}+\left(c-\frac{1}{x}\right)\cos\left(-xd\right)\right)^2+\left(\sin\left(g\right)\sqrt{y\left(b-d\right)^2+y\left(a-c\right)^2}+\left(c-\frac{1}{x}\right)\sin\left(-xd\right)\right)^2}+\frac{1}{x}$$
The second equation is
$$b=\arctan\left(\frac{\sin\left(g\right)\sqrt{y\left(b-d\right)^2+y\left(a-c\right)^2}+\left(c-\frac{1}{x}\right)\sin\left(-xd\right)}{\cos\left(g\right)\sqrt{y\left(b-d\right)^2+y\left(a-c\right)^2}+\left(c-\frac{1}{x}\right)\cos\left(-xd\right)}\right)$$
For each variable its value is the same in both equations.
How do I express x in terms of y for this set of equations?