a) $A$ is a symmetric $4\times 4$ matrix.
b) The rank of the matrix is $2$.
c) Vectors $ \langle1,2,0,1\rangle$ and $ \langle0,1,1,0\rangle$ are eigen vectors with eigenvalue $2$.
a) $A$ is a symmetric $4\times 4$ matrix.
b) The rank of the matrix is $2$.
c) Vectors $ \langle1,2,0,1\rangle$ and $ \langle0,1,1,0\rangle$ are eigen vectors with eigenvalue $2$.
On
Since the rank of $A$ is $2$ so by the rank-nullity theorem the dimension of the kernel of $A$ is $2$ so $0$ is an eigenvalue with multiplicity $2$ and since $A$ is symmetric then it's diagonalizable so there is an orthogonal basis of eigenvectors of $\Bbb R^4$ hence denote the given vectors $e_1,e_2$ and take two linearly independent vectors $e_3,e_4$ in the subspace $(\operatorname{span}(e_1,e_2))^\perp$.
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