How do I go about calculating the perimeter of a triangle that consists of three vertices of a cube?

Question

I'm given a unit cube. The task is to find the perimeter of triangle ACE. I have no other information, but considering it's a unit cube that should be more than enough.

Am I looking for an answer like this by any chance?

Anyways, cheers!

Answer 1

The question would have been more specific if the annotation of the vertices were given. So, the edges of the triangle can either be 1. a surface diagonal i.e., the diagonal connecting the running along the surface of the cube, 2. a body diagonal i.e., the diagonal connecting the vertices at opposite ends of the cube 3. an edge. Egde = a = 1
surface diagonal = s = $\sqrt{a^2 + a^2}$ = $\sqrt{1^1 + 1^1}$ = $\sqrt{2}$
body diagonal =$ \sqrt{a^2 + s^2} = \sqrt{1^2 + 2} = \sqrt{3}$

see which of these three are the edges of your triangle and add them.