How do I isolate the x

Question

How do I isolate and solve for the the $x$ in $x^ \frac 23 = 9$ and do the inverse on the other side of the RHS?

$x$ > 0 was part of the original question.

Answer 1

Hint:

$$a^{\frac mn}=\sqrt[n]{a^m}$$

Answer 2

$$ x^\frac{2}{3} = 9 $$ You can raise both sides to the 3rd power to get $$ (x^\frac{2}{3})^3 = 9^3\\ x^{3 \cdot\frac{2}{3}} = 9^3\\ x^{2} = 9^3 $$ Now you can take a square root on both sides to get $$ x = \pm \sqrt{9^3} = \pm \sqrt{ 3^6 } = \pm 3^3. $$