I'm supposed to prove that $$ a^2+b^2 > \dfrac{1}{2}a^2+ab+\dfrac{1}{2}b^2 $$
2026-04-13 13:38:34.1776087514
How do I prove that one term is greater than the other?
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1
HINT...consider multiplying out $\frac 12(a-b)^2$