How do I prove that the integral ${\displaystyle\int_0^1}{\dfrac{\ln(x)}{1-x^2}dx}$ converges?

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How do I prove that the integral ${\displaystyle\int_0^1}{\dfrac{ln(x)}{1-x^2}dx}$ converges?
I tried to find a converging on $[0,1]$ function $g(x)$ such as $g(x) > \dfrac{-ln(x)}{1-x^2}$, but I couldn't succeed in finding it as of yet.