How do I simplify this algebraic fraction?

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$$1-3(1/(3+x))+4(1/(3+x))^2$$ to $$(4+3x+x^2)/(9+6x+x^2) ?$$

I can see the denominator $(9+6x+x^2)$ is a result of squaring out the brackets $(3+x)^2$ but I am stuck after that....