I have the expression $$e^{log(3)* log(7)\over log 2}$$
I know it can be simplified to $$3^{log(7)\over log(2)}$$ But I don't know how its done.
I have the expression $$e^{log(3)* log(7)\over log 2}$$
I know it can be simplified to $$3^{log(7)\over log(2)}$$ But I don't know how its done.
HINT $$e^{k \log(a)} = \left(e^{\log(a)} \right)^k = a^k$$