$316.45 = 100e^{\delta(10)} + 100e^{\delta(5)}$
I don't know why I can't do this. I thought of using $\ln$ but I don't think $\ln(A+B) = \ln(A) + \ln(B)$ or does it?
$316.45 = 100e^{\delta(10)} + 100e^{\delta(5)}$
I don't know why I can't do this. I thought of using $\ln$ but I don't think $\ln(A+B) = \ln(A) + \ln(B)$ or does it?
Hint: Let $x = e^{5\delta}$. Notice that $e^{10\delta} = (e^{5\delta})^2$. Then we have
$$316.45 = 100x^2 + 100x$$
Solve as usual for $x$, and retrieve $\delta$ afterwards.