I want to solve this equation: $(0.2)^{(-x+3)}=125^{(2x+3)}$.
The correct answer is $-2.4$, however I end up getting $12$.
I'm following these steps:
$(0.2)^{(-x+3)}=125^{(2x+3)}$
$125^{(3x-9)}=125^{(2x+3)}$
$3x-9=2x+3$
$x=12$
2026-04-15 13:06:13.1776258373
How do I solve this equation: $(0.2)^{(-x+3)}=125^{(2x+3)}$
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Note that $0.2=\frac15=5^{-1}$. So we have: $$(5^{-1})^{3-x}=(5^3)^{2x+3} \Rightarrow 5^{x-3}=5^{6x+9}$$
and that's equivalent to $x-3=6x+9$.