How do u prove $\sum_{k=0}^n\frac{1}{2^{k}}\binom{n+k}{n} = 2^{n}$?

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Here is the expression

$$\sum_{k=0}^n\frac{1}{2^{k}}\binom{n+k}{n} = 2^{n}$$

How to go about proving this? I tried expanding the expression and it seems that $n+1$ must be even. But it isn't helping much. Can someone please help? Can this be proved using generating functions or combinatorics?