How do we get $S(m) = S(m/2) + \lg m$ from $T(n) = T(\sqrt{n}) + \lg\lg n$?

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I am confused about example we got today in class. Here is a recurrence and I am not sure how we got

$S(m)=S(m/2)+(\lg m)$

$$T(n)=T(\sqrt{n}) + (\lg\lg n) $$ Let $$m =\lg n$$ $$S(m)=S(m/2)+(\lg m) $$

Case2 of MT $$ ((\lg\lg n)^2)$$

How did we get m/2 ?
$2^m = n$ and $\sqrt{2^m} = 2^{m/2}$ not $m/2$

Also why is it Case 2?