How do we prove if the following function
$f(x)=\frac{1}{x}$ $;x>0$
is uniformly continous in $x>\frac{1}{2}$ and not uniformly continous everywhere
and
$f(x)=x^{n}$ is uniformly continous in [$\frac{1}{2},\frac{3}{4}$] and not in [0,1].
How do we prove if the following function
$f(x)=\frac{1}{x}$ $;x>0$
is uniformly continous in $x>\frac{1}{2}$ and not uniformly continous everywhere
and
$f(x)=x^{n}$ is uniformly continous in [$\frac{1}{2},\frac{3}{4}$] and not in [0,1].
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