The square-root of 5 is irrational. [ 5: the number five; x · y: the product of x and y; I(x): x is a nonzero integer]
I tried to form some logical equivalences and identities, but they seemed to be incorrect.
The square-root of 5 is irrational. [ 5: the number five; x · y: the product of x and y; I(x): x is a nonzero integer]
I tried to form some logical equivalences and identities, but they seemed to be incorrect.
We can also express your sentence as "There is no rational number, whose square is five". This yields the following expression: $$\neg\exists a, b \in \mathbb Z: I(b) \land \left(\frac ab\right)^2 = 5$$ Rearranging a bit to use only your terms, we have $$\neg\exists a, b: (I(a) \lor a = 0) \land I(b) \land a\cdot a = 5\cdot b\cdot b$$ Although this does not allow negative rational Numbers since you didn't give a symbol for that. Of course, since technically speaking the square root of a number always has to be positive, the expression remains correct.