Use epsilon-delta definition of the limit to show that the limit as $x$ approaches $0$ of $(-5x+6)=6$.
I have done these before, but I get confused because of the $-5x$. This is probably more of a weakness in my algebra than calculus.
$$\begin{align*} |f(x)-L| &< \varepsilon, \\ |-5x+6-6| &< \varepsilon, \\ |-5x| &< \varepsilon, \\ -\varepsilon < -5x &< \varepsilon, \\ \end{align*}$$
When I remove the $-5$, what happens with the greater than and less than signs?
Thank you for your support.