how does replacing $x$ with $x-h^2t$ where $h=h(x,t)$ transform an equation?

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I'm working on modelling a drip running down a wall, which is modelled at $t=0$

by

$h=1+e^{-x^2}$

And as $t$ increases, I've found it to be modelled by

$h=1+e^{-(x-h^2t)^2}$

Obviously, subbing $h$ into itself doesn't help whatsoever

I want to sketch how the drop would look like, and how far down the wall it would be at $t=0,1,2,3$ to illustrate what's happening. I'm also asked why this model might break down...

The obvious thing I can see is that its shifted $h^2t$ to the right, but of course, $h$ depends on $x,t$ which confuses me.

Any help with how this transformation makes the drip behave would be massively appreciated here is the full question