Let $H$ be some Hilbert space. Now in general, in quantum mechanics, the vector space representing states of $n$ (non-interacting) particles is $H^{\otimes n}$, but if I consider these particles of be fermions, the space becomes $\Lambda^n H$. So, given some wavefunctions $\psi_1,...,\psi_n$, if they represent fermions, the corresponding state in $\Lambda^n H$ is just $\psi_1 \wedge ... \wedge \psi_n$, which can then in turn be regarded as an element of $H^{\otimes n}$, using the embedding $\iota: \Lambda^n H \to H^{\otimes n}$.
Now $\iota (\psi_1 \wedge ... \wedge \psi_n) \neq \psi_1 \otimes ... \otimes \psi_n$, so somehow a particle is definitely more than just a wave function, but I guess it's also more than just wave functions together with a 'boson' and 'fermion' flag (because this seems just absurd).
I've heard that elementary particles are just irreducible representations, but is this the solution to this problem?
Also, the difference $\psi_1 \otimes ... \otimes \psi_n - \iota (\psi_1 \wedge ... \wedge \psi_n)$ is symmetric, so it seems to be some kind of boson. Does this have a meaning in physics?
I am not particularly experienced in many-body Quantum Mechanics, but is it not customary to represent the Hilbert Space of a many-body system by the Fock Space, defined by: $$F_{\nu} = \bigoplus_{N=1}^{\mathcal{N}} S_{\pm}\mathcal{H}^{\otimes n}$$ Where $S_{\pm}$ is the appropriate symmetrization operator (which is the distinction between Fermions and Bosons). The wikipedia page seems very useful for this, as is this article.