How does
$$(xy' + x'y)'$$
simplify to
$$(xy + x'y')$$
2026-04-06 22:34:29.1775514869
How does $(xy' + x'y)'$ simplify to $(xy + x'y')$
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1
By de Morgan laws : $$(xy'+x'y)'=(x'+y)(x+y')=x'x+x'y'+yx+yy'=xy+x'y'$$ because $xx'=yy'=0$.
(BTW, I suppose $x'$ means $\overline x$, or $\neg x$...)