$IX=AX$
So for the above equation, X is the eigenvector corresponding to the eigenvalues of 1. Let's multiply each column of A with a positive number bigger than one and call the new matrix B where A and B both are square matrices and I is the identity matrix.
$IX^{'}=BX^{'}$
My question is that what can we say about the $X^{'}$ Can we say all elements of $X^{'}$ are bigger than $X$?