How fast does the sequence $(1+1/n)^n$ converge to $\mathrm{e}$?
Is the difference more like $\frac1n$ or more like $\mathrm{e}^{-n}$?
How fast does the sequence $(1+1/n)^n$ converge to $\mathrm{e}$?
Is the difference more like $\frac1n$ or more like $\mathrm{e}^{-n}$?
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Observe that $$ \left(1+\frac{1}{n}\right)^n=\mathrm{e}^{n\log(1+\frac{1}{n})} =\mathrm{e}^{n(\frac{1}{n}-\frac{1}{2n^2}+\mathcal O(n^{-3}))} =\mathrm{e}\cdot\mathrm{e}^{-\frac{1}{2n}+\mathcal O(n^{-2}))}=\mathrm{e}\left(1-\frac{1}{2n}+\mathcal O(n^{-2})\right) $$ Hence $$ \left(1+\frac{1}{n}\right)^n-\mathrm{e}=-\frac{\mathrm{e}}{2n}+\mathcal O(n^{-2}) $$