How is $\sqrt{3} * \sqrt{2} = \sqrt{6}$ mathematically possible?

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Well, this question is basically a method to point a loophole in Maths which I'm not sure how it is possible...

Let us take a number A and another no. K.
A + A + A + A + A........(k times) = K * A

Everything is all right till here. But the problem arises in the next step.

We know taking A = $\sqrt{3}$ and K = $\sqrt{2}$, the answer is $\sqrt{6}$

But how can we add $\sqrt{3}$ $\sqrt{2}$ times ?

Or, to reframe the question, how can we find the answer of multiplication of two irrational numbers when we know it is not possible to add a number (or infact, do anything), irrational times to itself.

Using the fact that multiplication is repeated addition.

Basically, the above points out that multiplication isn't repeated addition. (Andre Nicolas)