How is $\sum\limits_{k=2}^{\infty} \frac{k^e}{k^\pi}$ divergent?

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Can somebody explain to me how this series diverges by using the P-Series test?

$$\sum_{k=2}^{\infty} \frac{k^e}{k^\pi}$$

My guess was convergence, due to $p > 1$, because $p = \pi$. However, according to Wolframalpha it diverges.

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Hint: rewrite it as

$$\sum_{k=2}^{\infty} \frac{k^e}{k^{\pi}} = \sum_{k=2}^{\infty} \frac{1}{k^{\pi-e}}.$$

What is your $p$ here?