I'm confused by the definition of the material conditional.
In my implementation of propositional-logic I have the following definition of the material conditional:
$$\frac{P\to{Q}}{\neg(P\land\neg{Q})}\quad\small\text{[MaterialConditionalElimination]}$$
$$\frac{\neg(P\land\neg{Q})}{P\to{Q}}\quad\small\text{[MaterialConditionalIntroduction]}$$
I should that this is a definition because there is (effectively) a bi-directional inference rule. That is to say, whenever you encounter $\neg(P\land\neg{Q})$ you can replace it by $P\to{Q}$ and vice-versa.
However, according to Wikipedia, only the first of these rules is found in minimal logic. But I cannot see how you can derive the second from the first with the addition of the principle of explosion. Also, it is the second that serves, if one rule only can be taken, as a definition, because that is the rule that introduces the new $\to$ connective.
Update: It seems that the material conditional does not find its way into propositional logic when defined in this natural deductive style. I have therefore taken it out of the aforementioned implementation.
Further update: Well, it appears that it does, but only at the classical level. At this level, however, it is equivalent to logical consequence $\Rightarrow$ and therefore I am opting to leave it out still.
The implication sign does not denote material implication in intuitionistic logic. The Wikipedia page does not say what you think it does. It says that $\lnot P \lor Q$ (not $\lnot (P \land \lnot Q)$) entails $P \to Q$ in intuitionistic logic, but not in minimal logic (which is true but the reverse entailment is not provable in intuitionistic logic). In intuitionistic logic (and hence also in minimal logic) $\lnot P \lor Q$ is not equivalent to $\lnot(P \land \lnot Q)$ and neither of those is equivalent to $P \to Q$.
To see that $\lnot P \lor Q$ is strictly stronger than $P \to Q$ in intuitionistic logic, take $P \equiv Q$ for $P$ a variable, then $P \to P$ is provable, but $\lnot P \lor P$ expresses the intuitionistically unacceptable law of the excluded middle. To see that $P \to Q$ is strictly stronger than $\lnot(P \land \lnot Q)$, take $Q$ to be a variable and take $P = \lnot\lnot Q$, then $\lnot(\lnot\lnot Q \land \lnot Q)$ is provable, but $\lnot\lnot Q \to Q$ is the intuitionistically unacceptable principle of double-negation elimination.