How many circular permutations are there of the multiset:
$$\{3\cdot{a},4\cdot{b},2\cdot{c},1\cdot{d}\}$$
Note that if you "cut" the circle at whereever you placed the $d$, you just get a regular permutation of the remaining $9$ elements. Any such permutation yields a different circular permutation by adding back the $d$.
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Note that if you "cut" the circle at whereever you placed the $d$, you just get a regular permutation of the remaining $9$ elements. Any such permutation yields a different circular permutation by adding back the $d$.