This is a very basic pre-algebra problem. I think I solved it (pretty confident) and went to check to see if there were any posted solutions online. Of course, anyone can answer, so there are a myriad of different answers. Here's the problem, then my solution.
There are 7 girls on a bus.
Each girl has 7 backpacks.
In each backpack, there are 7 big cats.
For every big cat, there are 7 little cats.
Question: How many legs are there in the bus (minus the driver)?
So, if there is a big cat, there are seven little cats, so 32 cat legs per big cat.
There are 7 big cats per back pack, so there are 224 cat legs per back pack.
But there are 7 back packs per girl, so there are 1568 cat legs per girl.
But there are 7 girls on the bus, so there are 10976 cat lets on the bus.
But there are 7 girls with 2 legs each. So 14 girl legs.
So 10976+14=10990 total lets.
Is this correct? Many sites give a much lower answer.
Yes, everything looks correct, except you forgot the bus driver.