Child tickets - $\$7$
Adult Tickets - $\$10$
Senior Tickets - $\$5$
Day one sold $678$ tickets for $\$5,812$
Day two sold $535$ tickets for $\$4,541$
How many of each ticket were sold on day one and two?
If someone could even just explain how to set it up or what method to use I would appreciate it a lot. Thank you!
On
Child tickets - $7
Adult Tickets - $10
Senior Tickets - $5
A is the number of Adult tickets, C is the number of Child tickets, and S is the number of Senior tickets in what follows below.
A1 + C1 + S1 = 678 (Day 1)
A2 + C2 + S2 = 535 (Day 2)
Solution:
Day one: Sold tickets 678 for $5,812
A1 = 420, C1 = 161, S1 = 97 (Day 1)
Day two: Sold tickets 535 for $4,541
A2 = 215, C2 = 38, S2 = 425 (Day 2)
It must be remembered that other answers are also possible.
Let $x$ be the number of child tickets sold, $y$ adults, and $z$ seniors. Then we know for day one $$ \$x + \$y + \$z = \$ 5812 $$ and $$ x + y + z = 678. $$ What are the dollar amounts associated with $x,y$, and $z$? What does day two look like?